Problem 1: Write a program to check a number is Smith or not. [Digits of Smith number when added is equal to sum of digits of prime factors of the number. 27 is Smith number because 2+7=9 and 27=333]
Solution
import java.util.Scanner;
class Smith {
public static boolean isPrime(int n) {
if (n <= 1)
return false;
for (int i = 2; i <= Math.sqrt(n); i++) {
if (n % i == 0)
return false;
}
return true;
}
public static int sumOfDigit(int n) {
int sum = 0;
while (n > 0) {
sum = sum + n % 10;
n = n / 10;
}
return sum;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter a number: ");
int n = sc.nextInt();
int k=n, s=0;
for (int i = 2; i <= n; i++) {
if (isPrime(i)) {
while (k % i == 0) {
k = k / i;
s = s + sumOfDigit(i);
}
}
}
if (sumOfDigit(n) == s)
System.out.println(n + " is Smith number");
else
System.out.println(n + " is not Smith number");
sc.close();
}
}
Output
Enter a number:
27
27 is Smith number
Enter a number:
12
12 is not Smith number
Problem 2: Write a program to check whether a number is Kaprekar. [A Kaprekar number's square can be split into two parts that add up to the original number. 45 is Kaprekar number because 45^2 = 2025 and 20+25=45].
Solution
import java.util.Scanner;
class Kaprekar {
public static int noOfDigits(int n) {
int count = 0;
while (n > 0) {
count++;
n = n / 10;
}
return count;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter a number: ");
int n = sc.nextInt();
int c = noOfDigits(n);
int sq = n * n;
int l = sq / (int) Math.pow(10, c);
int r = sq % (int) Math.pow(10, c);
if (l + r == n)
System.out.println(n + " is Kaprekar number");
else
System.out.println(n + " is not Kaprekar number");
sc.close();
}
}
Output
Enter a number:
45
45 is Kaprekar number
Enter a number:
10
10 is not Kaprekar number
Problem 3: Write a program to find out the given number is a ISBN number or not. [ISBN is a 10 digit number where the last digit is a check digit. The check digit is calculated as (10a1+9a2+8a3+7a4+6a5+5a6+4a7+3a8+2*a9)%11 and if the check digit is 10 then it is represented as X]
Solution
import java.util.Scanner;
class ISBN {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter a number: ");
int n = sc.nextInt();
int sum = 0;
int a = n;
int i = 10;
while (a > 0) {
int r = a % 10;
sum = sum + r * i;
a = a / 10;
i--;
}
int checkDigit = sum % 11;
if (checkDigit == 10)
System.out.println(n + " is ISBN number");
else
System.out.println(n + " is not ISBN number");
sc.close();
}
}
Output
Enter a number:
950126105537
950126105537 is ISBN number
Enter a number:
950126105538
950126105538 is not ISBN number
Problem 4: Write a program to check whether a number is Disarium. [A Disarium number is a number where the sum of its digits powered with their respective positions is equal to the number itself. 175 is Disarium number because 1^1+7^2+5^3=175]
Solution
import java.util.Scanner;
class Disarium {
public static int noOfDigits(int n) {
int count = 0;
while (n > 0) {
count++;
n = n / 10;
}
return count;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter a number: ");
int n = sc.nextInt();
int c = noOfDigits(n);
int sum = 0;
int a = n;
int i = 1;
while (a > 0) {
int r = a % 10;
sum = sum + (int) Math.pow(r, i);
a = a / 10;
i++;
}
if (sum == n)
System.out.println(n + " is Disarium number");
else
System.out.println(n + " is not Disarium number");
sc.close();
}
}
Output
Enter a number:
175
175 is Disarium number
Enter a number:
176
176 is not Disarium number
Problem 5: Write a program to check whether a number is Keith. [A Keith number isis a number that appears in a sequence generated from its own digits, where the sequence starts with the digits of the number, and each new term is the sum of the previous k terms (k being the number of digits). For example, 197 (3 digits) starts a sequence: 1, 9, 7, (1+9+7)=17, (9+7+17)=33, (7+17+33)=57, (17+33+57)=107, (33+57+107)=197; since 197 appears, it's a Keith number.]
Solution
import java.util.Scanner;
class Keith {
public static int noOfDigits(int n) {
int count = 0;
while (n > 0) {
count++;
n = n / 10;
}
return count;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter a number: ");
int n = sc.nextInt();
int c = noOfDigits(n);
int[] arr = new int[c];
int a = n;
int i = 0;
while (a > 0) {
arr[i] = a % 10;
a = a / 10;
i++;
}
int sum = 0;
for (int j = 0; j < c; j++) {
sum = sum + arr[j];
}
while (sum != n) {
for (int j = 0; j < c - 1; j++) {
arr[j] = arr[j + 1];
}
arr[c - 1] = sum;
sum = 0;
for (int j = 0; j < c; j++) {
sum = sum + arr[j];
}
}
if (sum == n)
System.out.println(n + " is Keith number");
else
System.out.println(n + " is not Keith number");
sc.close();
}
}
Output
Enter a number:
197
197 is Keith number
Enter a number:
198
198 is not Keith number
Problem 6: Write a program to generate a Pascal Triangle for n rows. [Pascal's Triangle is a triangular array of the binomial coefficients. The rows of Pascal's Triangle are conventionally enumerated starting with row 0 at the top.]
Solution
import java.util.Scanner;
class PascalTriangle {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the number of rows: ");
int n = sc.nextInt();
int[][] arr = new int[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j <= i; j++) {
if (j == 0 || j == i)
arr[i][j] = 1;
else
arr[i][j] = arr[i - 1][j - 1] + arr[i - 1][j];
}
}
for (int i = 0; i < n; i++) {
for (int j = 0; j < n - i - 1; j++) {
System.out.print(" ");
}
for (int j = 0; j <= i; j++) {
System.out.print(arr[i][j] + " ");
}
System.out.println();
}
sc.close();
}
}
Output
Enter the number of rows:
5
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
Problem 7: Write a program to find GCD using recursive function. [GCD is the greatest common divisor of two numbers. It is the largest number that divides both numbers without leaving a remainder.]
Solution
import java.util.Scanner;
class GCD {
public static int gcd(int a, int b) {
if (b == 0)
return a;
else
return gcd(b, a % b);
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter two numbers: ");
int a = sc.nextInt();
int b = sc.nextInt();
System.out.println("GCD of " + a + " and " + b + " is " + gcd(a, b));
sc.close();
}
}
Output
Enter two numbers:
48 18
GCD of 48 and 18 is 6
Solution
import java.util.Scanner;
class Permutation {
public static long fact(int n) {
if (n == 0)
return 1;
else
return n * fact(n - 1);
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the limit: ");
int n = sc.nextInt();
System.out.println("Enter the common factor: ");
int r = sc.nextInt();
long count = fact(n) / fact(n - r);
System.out.println("Number of permutations where product is divisible by " + r + " is " + count);
sc.close();
}
}
Output
Enter the limit:
12
Enter the common factor:
4
Number of permutations where product is divisible by 4 is 11880
Solution
import java.util.Scanner;
class Combination {
public static long fact(int n) {
if (n == 0)
return 1;
else
return n * fact(n - 1);
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the limit: ");
int n = sc.nextInt();
System.out.println("Enter the common factor: ");
int r = sc.nextInt();
long count = fact(n) / (fact(r) * fact(n - r));
System.out.println("Number of combinations where product is divisible by " + r + " is " + count);
sc.close();
}
}
Output
Enter the limit:
12
Enter the common factor:
4
Number of combinations where product is divisible by 4 is 495
Solution
import java.util.Scanner;
class APSeries {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the first term: ");
int a = sc.nextInt();
System.out.println("Enter the common difference: ");
int d = sc.nextInt();
System.out.println("Enter the number of terms: ");
int n = sc.nextInt();
int sum = 0;
System.out.println("AP series is: ");
for (int i = 0; i < n; i++) {
int term = a + i * d;
System.out.print(term + " ");
sum += term;
}
System.out.println("\nSum of AP series is: " + sum);
sc.close();
}
}
Output
Enter the first term:
2
Enter the common difference:
3
Enter the number of terms:
5
AP series is: 2 5 8 11 14
Sum of AP series is: 40
Solution
import java.util.Scanner;
class GPSeries {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the first term: ");
int a = sc.nextInt();
System.out.println("Enter the common ratio: ");
int r = sc.nextInt();
System.out.println("Enter the number of terms: ");
int n = sc.nextInt();
int sum = 0;
double product = 1;
System.out.println("GP series is: ");
for (int i = 0; i < n; i++) {
int term = (int) (a * Math.pow(r, i));
System.out.print(term + " ");
sum += term;
product *= term;
}
System.out.println("\nSum of GP series is: " + sum);
System.out.println("Product of GP series is: " + product);
sc.close();
}
}
Output
Enter the first term:
2
Enter the common ratio:
3
Enter the number of terms:
5
GP series is: 2 6 18 54 162
Sum of GP series is: 242
Product of GP series is: 1458
Problem 12: Write a program to change a number into a Roman number. [Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M.]
Solution
import java.util.Scanner;
class RomanNumber {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter a number: ");
int n = sc.nextInt();
String[] roman = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"};
int[] values = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
String result = "";
for (int i = 0; i < values.length; i++) {
while (n >= values[i]) {
result += roman[i];
n -= values[i];
}
}
System.out.println("Roman number is: " + result);
sc.close();
}
}
Output
Enter a number:
1987
Roman number is: MCMLXXXVII
Problem 13: Write a program to find denomination of a given amount.
Solution
import java.util.Scanner;
class Denomination {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the amount: ");
int amount = sc.nextInt();
int[] denominations = {1000, 500, 100, 50, 20, 10, 5, 2, 1};
int[] count = new int[denominations.length];
for (int i = 0; i < denominations.length; i++) {
count[i] = amount / denominations[i];
amount = amount % denominations[i];
}
System.out.println("Denomination of " + amount + " is: ");
for (int i = 0; i < denominations.length; i++) {
if (count[i] > 0)
System.out.println(denominations[i] + " x " + count[i]);
}
sc.close();
}
}
Output
Enter the amount:
1234
Denomination of 1234 is:
1000 x 1
200 x 1
100 x 2
20 x 1
10 x 3
4 x 2
Problem 14: Write a program to swap two strings without using third variable.
Solution
import java.util.Scanner;
class SwapStrings {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("Enter the first string: ");
String str = sc.nextLine();
System.out.println("Enter the second string: ");
String str1 = sc.nextLine();
str = str + str1;
str1 = str.substring(0, str.length() - str1.length());
str = str.substring(str1.length());
System.out.println("After swapping: ");
System.out.println("First string: " + str);
System.out.println("Second string: " + str1);
sc.close();
}
}
Output
Enter the first string:
Hello
Enter the second string:
World
After swapping:
First string: World
Second string: Hello
Problem 15: Write a program to display the below pattern
1 A A A A A
2 2 B B B B
3 3 3 C C C
4 4 4 4 D D
5 5 5 5 5 E
Solution
class Pattern {
public static void main(String[] args) {
char ch = 'A';
for (int i = 1; i <= 5; i++) {
for (int j = 1; j <= i; j++) {
System.out.print(i + " ");
}
for (int k = 1; k <= 5 - i; k++) {
System.out.print(ch + " ");
}
System.out.println();
ch++;
}
}
}
Problem 16: Write a program to enter a natural number and display all possible combinations of consecutive natural numbers that sum up to that number.
Solution
import java.util.Scanner;
class ConsecutiveSum {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter a natural number: ");
int n = sc.nextInt();
for (int i = 1; i <= n; i++) {
int sum = 0;
for (int j = i; j <= n; j++) {
sum += j;
if (sum == n) {
for (int k = i; k <= j; k++) {
System.out.print(k + " ");
}
System.out.println();
break;
} else if (sum > n) {
break;
}
}
}
sc.close();
}
}
Output
Enter a natural number: 15
1 2 3 4 5
4 5 6
7 8
15
Problem 17: Write a program to display the below pattern
11
12 22
13 23 33
14 24 34 44
15 25 35 45 55
Solution
import java.util.Scanner;
class Pattern {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter the number of rows: ");
int n = sc.nextInt();
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= i; j++) {
System.out.print(j + "" + i + " ");
}
System.out.println();
}
sc.close();
}
}
Problem 18: Write a program to display the below pattern
*************
* *
* *
* *
* *
* *
* *
* *
* *
*************
Solution
class Pattern {
public static void main(String[] args) {
int n = 10;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
if (i == 1 || i == n || j == 1 || j == n)
System.out.print("*");
else
System.out.print(" ");
}
System.out.println();
}
}
}
Problem 19: Write a program to check whether given pair of numbers are Twin Prime. [Twin primes are pairs of prime numbers that have a difference of 2.]
Solution
import java.util.Scanner;
class TwinPrime {
public static boolean isPrime(int n) {
if (n <= 1)
return false;
for (int i = 2; i <= Math.sqrt(n); i++) {
if (n % i == 0)
return false;
}
return true;
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter the first number: ");
int n1 = sc.nextInt();
System.out.print("Enter the second number: ");
int n2 = sc.nextInt();
if (isPrime(n1) && isPrime(n2) && Math.abs(n1 - n2) == 2)
System.out.println(n1 + " and " + n2 + " are Twin Primes.");
else
System.out.println(n1 + " and " + n2 + " are not Twin Primes.");
sc.close();
}
}
Output
Enter the first number:
3
Enter the second number:
5
3 and 5 are Twin Primes.
Problem 20: Write a program to merge two sorted arrays.
Solution
import java.util.Arrays;
import java.util.Scanner;
class MergeSortedArrays {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter the size of the first array: ");
int n = sc.nextInt();
int[] arr1 = new int[n];
System.out.print("Enter the elements of the first array: ");
for (int i = 0; i < n; i++)
arr1[i] = sc.nextInt();
System.out.print("Enter the size of the second array: ");
int m = sc.nextInt();
int[] arr2 = new int[m];
System.out.print("Enter the elements of the second array: ");
for (int i = 0; i < m; i++)
arr2[i] = sc.nextInt();
int[] mergedArray = new int[n + m];
int i = 0, j = 0, k = 0;
while (i < n && j < m) {
if (arr1[i] < arr2[j])
mergedArray[k++] = arr1[i++];
else
mergedArray[k++] = arr2[j++];
}
while (i < n)
mergedArray[k++] = arr1[i++];
while (j < m)
mergedArray[k++] = arr2[j++];
System.out.println("Merged sorted array: " + Arrays.toString(mergedArray));
sc.close();
}
}
Output
Enter the size of the first array:
3
Enter the elements of the first array: 1 3 5
Enter the size of the second array:
3
Enter the elements of the second array: 2 4 6
Merged sorted array: [1, 2, 3, 4, 5, 6]
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